F(x)=-6.02+1.50x-0.02x^2

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Solution for F(x)=-6.02+1.50x-0.02x^2 equation: 



(F)=-6.02+1.50F-0.02F^2

We move all terms to the left:

(F)-(-6.02+1.50F-0.02F^2)=0

We get rid of parentheses

0.02F^2-1.50F+F+6.02=0

We add all the numbers together, and all the variables

0.02F^2-0.5F+6.02=0

a = 0.02; b = -0.5; c = +6.02;
Δ = b2-4ac
Δ = -0.52-4·0.02·6.02
Δ = -0.2316
Delta is less than zero, so there is no solution for the equation

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